Armstrong Program In C

Armstrong Program In C. If the given number is equal to the sum of the power of n for each digit present in that integer then that number can be Armstrong Number in C programming For example 153 is an Armstrong Number in C programming because number of individual digits in 153 = 3 153 = 1³ + 5³ + 3³ = 1 + 125 + 27 = 153 How to calculate the power of an Armstrong number?.

Armstrong Number in C Using For Loop #include int main() { int numrsum=0temp printf(“Enter The Number”) scanf(“%d”&num) for(temp=numnum!=0num=num/10) { r=num % 10 sum=sum+(r*r*r) } if(sum==temp) printf(“%d is Armstrong Number\n”temp) else printf(“%d is Not Armstrong Number\n”temp) }.

Armstrong Number Program in C C Programs

First calculate the cube of its each digits 1^3 = (1*1*1) = 1 5^3 = (5*5*5) = 125 3^3= (3*3*3) = 27 Now add the cube 1+125+27 = 153 It means 153 is an Armstrong number Ok Then move on the program where your concept will be cleared ???? C Program to check a number is Armstrong or not.

C Program to Check Armstrong Number

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C/C++ program for Armstrong Numbers GeeksforGeeks

In the above program we have first initialized the required variable num = it will hold the integer value i = it will hold the integer value Taking the input integer number from the user Checking the number is a prime number Armstrong number or perfect.